document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=264159>Question 264159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The volume of a cube with sides of length s is given by V = s^3. Find the rate of change of the volume with respect to s when s = 2 centimeters. \r<BR>\n" );
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document.write( "V '(2) = _____ cm2 <BR>\n" );
document.write( "i found the derivative to be V'= 3s^2 so V'(2)= 36? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194591 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume of a cube with sides of length s is given by V = s^3. Find the rate of change of the volume with respect to s when s = 2 centimeters. \r<BR>\n" );
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document.write( "V '(2) = _____ cm2 <BR>\n" );
document.write( "i found the derivative to be V'= 3s^2 so V'(2)= 36?<BR>\n" );
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document.write( "Your method is good, but<BR>\n" );
document.write( "V'(2) = 3*2^2 = 12<BR>\n" );
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