document.write( "Question 263906: s^2 = t^-1 and t^1/4 = u^-1/3, then what is the value of s in terms of u? \n" ); document.write( "
Algebra.Com's Answer #194576 by ankor@dixie-net.com(22740)\"\" \"About 
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s^2 = t^-1 and t^1/4 = u^-1/3, then what is the value of s in terms of u
\n" ); document.write( ":
\n" ); document.write( "\"s%5E2+=+t%5E-1\"
\n" ); document.write( "Reciprocal gets rid of the neg exponent
\n" ); document.write( "\"s%5E2+=+1%2Ft\"
\n" ); document.write( "then
\n" ); document.write( "\"s+=+sqrt%281%2Ft%29\"
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\n" ); document.write( ":
\n" ); document.write( "\"t%5E%281%2F4%29+=+u%5E%28-1%2F3%29\"
\n" ); document.write( "Raise both side to the 4th power
\n" ); document.write( "\"t+=+u%5E%28-4%2F3%29\"; (this is -4/3 power)
\n" ); document.write( ":
\n" ); document.write( "Replace t in \"s+=+sqrt%281%2Ft%29\"
\n" ); document.write( "\"s+=+sqrt%281%2Fu%5E%28-4%2F3%29%29%29\"
\n" ); document.write( "Reciprocal gets rid of the neg exponent
\n" ); document.write( "\"s+=+sqrt%28u%5E%284%2F3%29%29%29\"
\n" ); document.write( "We can also write the square root like this
\n" ); document.write( "\"s+=+u%5E%28%284%2F3%29%2A%281%2F2%29%29\"
\n" ); document.write( "which is
\n" ); document.write( "\"s+=+u%5E%282%2F3%29%29\"; (exponent is 2/3)\r
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