document.write( "Question 263906: s^2 = t^-1 and t^1/4 = u^-1/3, then what is the value of s in terms of u? \n" ); document.write( "
Algebra.Com's Answer #194576 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! s^2 = t^-1 and t^1/4 = u^-1/3, then what is the value of s in terms of u \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Reciprocal gets rid of the neg exponent \n" ); document.write( " \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Raise both side to the 4th power \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Replace t in \n" ); document.write( " \n" ); document.write( "Reciprocal gets rid of the neg exponent \n" ); document.write( " \n" ); document.write( "We can also write the square root like this \n" ); document.write( " \n" ); document.write( "which is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |