document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33039>Question 33039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please solve this for me? I have to solve this using factoring: \r<BR>\n" );
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document.write( "The length of a rectangle is 6cm less than twice its width. Find the dimensions of the rectangle if its area is 108cm2(squared)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19457 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width be x<BR>\n" );
document.write( "then length=(2x-6)\r<BR>\n" );
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document.write( "area is length into breadth\r<BR>\n" );
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document.write( "x(2x-6)=108<BR>\n" );
document.write( "2x^2-6x-108=0<BR>\n" );
document.write( "x^2-3x-54=0<BR>\n" );
document.write( "(x-9)(x+6)=0<BR>\n" );
document.write( "x=9,-6\r<BR>\n" );
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document.write( "width cannot be negative\r<BR>\n" );
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document.write( "hence x=9\r<BR>\n" );
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document.write( "length=2x-6=18-6=12<BR>\n" );
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document.write( "xC </SPAN>\n" );
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