document.write( "Question 264140: find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third \n" ); document.write( "
Algebra.Com's Answer #194507 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LET X, X+1 & X+2 BE THE 3 INTEGERS. \n" ); document.write( "2X+4(X+1)=2(X+2)+20 \n" ); document.write( "2X+4X+4=2X+4+20 \n" ); document.write( "2X+4X-2X=24-4 \n" ); document.write( "4X=20 \n" ); document.write( "X=20/4 \n" ); document.write( "X=5 ANS. FOR THE FIRST INTEGER. \n" ); document.write( "5+1=6 FOR THE NEXT INTEGER. \n" ); document.write( "5+2=7 FOR THE LARGEST INTEGER. \n" ); document.write( "PROOF: \n" ); document.write( "2*5+4*6=2*7+20 \n" ); document.write( "10+24=14+20 \n" ); document.write( "34=34 \n" ); document.write( " |