document.write( "Question 264140: find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third \n" ); document.write( "
Algebra.Com's Answer #194507 by checkley77(12844)\"\" \"About 
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LET X, X+1 & X+2 BE THE 3 INTEGERS.
\n" ); document.write( "2X+4(X+1)=2(X+2)+20
\n" ); document.write( "2X+4X+4=2X+4+20
\n" ); document.write( "2X+4X-2X=24-4
\n" ); document.write( "4X=20
\n" ); document.write( "X=20/4
\n" ); document.write( "X=5 ANS. FOR THE FIRST INTEGER.
\n" ); document.write( "5+1=6 FOR THE NEXT INTEGER.
\n" ); document.write( "5+2=7 FOR THE LARGEST INTEGER.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*5+4*6=2*7+20
\n" ); document.write( "10+24=14+20
\n" ); document.write( "34=34
\n" ); document.write( "
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