document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=264138>Question 264138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194498 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .65x+.40(20-x)=.50*20<BR>\n" );
document.write( ".65x+8-.40x=10<BR>\n" );
document.write( ".25x=10-8<BR>\n" );
document.write( ".25x=2<BR>\n" );
document.write( "x=2/.25<BR>\n" );
document.write( "x=8 gallons of 65% solution is used.<BR>\n" );
document.write( "20-8=12 gallons of 40% solution is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".65*8+.40*12=.50*20<BR>\n" );
document.write( "5.2+4.8=10<BR>\n" );
document.write( "10=10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );