document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=264004>Question 264004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have 20 gallons of a solution that is 40% alcohol, If I want to end up with 20 gallons of a 60% alcohol solution then how much pure alcohol would I have to add? HINT: If you add x number of gallons of pure alcohol, you first must take away x number of gallons of the 40% solution.\r<BR>\n" );
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document.write( "I have figured out the answer is 4 gallons, I just am not sure how to lay out the problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194461 by </B><A HREF=/tutors/aboutme.mpl?userid=JBarnum><B>JBarnum(2146)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JBarnum><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JBarnum><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194461\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"I have 20 gallons of a solution that is 40% alcohol\"<BR>\n" );
document.write( ".4(20)=8 gallons of alcohol and 12 gallons of solution<BR>\n" );
document.write( ".6(20)=12 gallons of alcohol and 8 of solution<BR>\n" );
document.write( "12gallons - 8 gallons makes 4 gallons more needed of alcohol, but if you just add 4 more gallons you get 24gallons so u have to subtract 4 gallons first and then add 4 pure alcohol<BR>\n" );
document.write( "i cant seem to get an equation for it, maybe someone else can help out  </SPAN>\n" );
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