document.write( "Question 263976: For a certain three digit positive number the ones digit is 3 times the hundreds digit. The tens digit is 1 less than the ones digit. The ones digit is 15 less than the product of the hundreds and tens digit. What digit is the ones digit? \n" ); document.write( "
Algebra.Com's Answer #194441 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! For a certain three digit positive number the ones digit is 3 times the hundreds digit. The tens digit is 1 less than the ones digit. The ones digit is 15 less than the product of the hundreds and tens digit. What digit is the ones digit? \r \n" ); document.write( "\n" ); document.write( "first take each line by line \n" ); document.write( "\"For a certain three digit positive number\" means: xyz \n" ); document.write( "using xyz as the 3 digit number: ones digit= z, tens digit= y, hundreds digit=x \n" ); document.write( "\"ones digit is 3 times the hundreds digit\"means: z=3x \n" ); document.write( "\"The tens digit is 1 less than the ones digit\" means: y=z-1 \n" ); document.write( "\"The ones digit is 15 less than the product of the hundreds and tens digit\" means: z=xy-15 \n" ); document.write( "\"What digit is the ones digit?\" means z=?\r \n" ); document.write( "\n" ); document.write( "since we are looking for z rearange the first equation z=3x to x=z/3 so relist your equations: \n" ); document.write( "x=z/3 y=z-1 z=xy-15 \n" ); document.write( "we want to find value for z and they give value for y and you just got the value for x, so in the third equation put the z/3 for x and the z-1 for y: \n" ); document.write( "z=xy-15 \n" ); document.write( "z=((z/3)(z-1))-15 now simplify \n" ); document.write( "z= ((z^2-z)/3)-15 id get rid of the fraction by multiplying everything by 3 \n" ); document.write( "3z= z^2-z-45 subtract 3z from both sides \n" ); document.write( "0= z^2-z-45-3z simplify \n" ); document.write( "0= z^2-4z-45 Standard Quadratic equation A=1 B=-4 C=-45 \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To reiterate the question that you gave us to solve\r \n" ); document.write( "\n" ); document.write( "\"What digit is the ones digit?\" \n" ); document.write( "I did answer it, check the quadratic equation again (x=9,-5), and since it cant be negative the ones digit must be 9.\r \n" ); document.write( "\n" ); document.write( "**oh and if you want to know what the other 2 digits are reread the question knowing the ones digit is 9 so we know xy9 \n" ); document.write( "9/3=x x=3 now we know 3y9 \n" ); document.write( "y=9-1=8 now we know 389. but this number isnt the answer to the question you stated above\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |