document.write( "Question 263977: solve.\r
\n" ); document.write( "\n" ); document.write( "sqrt(9x+67)=x+5\r
\n" ); document.write( "\n" ); document.write( "The solution is x=
\n" ); document.write( "(simplify answer).\r
\n" ); document.write( "\n" ); document.write( "Please help me solve.
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Algebra.Com's Answer #194438 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint: If you square both sides of \"sqrt%289x%2B67%29=x%2B5\" you get \"9x%2B67=%28x%2B5%29%5E2\". FOIL out the right side to get \"9x%2B67=x%5E2%2B10x%2B25\"\r
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\n" ); document.write( "\n" ); document.write( "From there, get every term to one side to get \"x%5E2%2Bx-42=0\". Now either factor or use the quadratic formula to solve for 'x'. Don't forget to check your answers by plugging them back into \"sqrt%289x%2B67%29=x%2B5\"
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