document.write( "Question 263926: The length of a rectangle is 10 centimeters less than 3 times its width. If the perimeter of the rectangle is at most 180 centimeters, find the greatest possible length of the rectangle \r
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document.write( "Can You Please Show How You Got Your Answer \n" );
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Algebra.Com's Answer #194425 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 10 centimeters less than 3 times its width. If the perimeter of the rectangle is at most 180 centimeters, find the greatest possible length of the rectangle \n" ); document.write( "Can You Please Show How You Got Your Answer \r \n" ); document.write( "\n" ); document.write( "L length, W width \n" ); document.write( "P perimeter = 2 * (L + W) = 180 cm at most \n" ); document.write( "P = 2 * ( (3 * W - 10) + W ) = 180 \n" ); document.write( "2 * ( (3 * W - 10) + W ) = 180 (solve for W) \n" ); document.write( "3 * W - 10 + W = 90 (divided both sides by 2) \n" ); document.write( "4 * W - 10 = 90 \n" ); document.write( "4 * W = 100 (divide both sides by 4) \n" ); document.write( "W = 25 cm \n" ); document.write( "L = 3 * W - 10 (plug in the solved W) \n" ); document.write( "L = 3 * 25 - 10 \n" ); document.write( "L = 75 - 10 \n" ); document.write( "L = 65 cm greatest possible length\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "P = 2 * (L + W) \n" ); document.write( "P = 2 * (65 + 25) \n" ); document.write( "P = 2 * 90 \n" ); document.write( "P = 180 cm\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |