document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263914>Question 263914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this problem?\r<BR>\n" );
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document.write( "The measure of the angle's supplement is 50 more than five times that of its complement. Find the measure of the angle described? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194415 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "We know that when two angles equal 180 degrees they are supplementary angles, right? So let's represent x to be the complement therefore we can write the other as 5x+50. <BR>\n" );
document.write( "x + 5x+50=180 Combine terms and subtract 50 from both sides to get:<BR>\n" );
document.write( "6x=130 Divide both sides by 6 to get:<BR>\n" );
document.write( "x=21 2/3 degrees is one angle and the other is 158 1/3 degrees. <BR>\n" );
document.write( "RJ <BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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