document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263884>Question 263884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve the equation, 5/7x+1/3=2/5-2/7x+2/5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194414 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "(Note: I'm assuming the equation is like this 5/7(x)+1/3=2/5-2/7(x)+2/5))<BR>\n" );
document.write( "5/7(x)+1/3=2/5-2/7(x)+2/5 First add 2/7(x) to both sides and combine 2/5 and 2/5 to get:<BR>\n" );
document.write( "7/7(x)+1/3=4/5 Now subtract 1/3 from both sides to get:<BR>\n" );
document.write( "x=7/15<BR>\n" );
document.write( "There are a couple ways to tackle this problem but this is the quickest. <BR>\n" );
document.write( "RJ<BR>\n" );
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document.write( "www.math-unlock.com </SPAN>\n" );
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