document.write( "Question 263823: A manufacturer of tire found out that 2 % of his production was defective.
\n" ); document.write( "If you have just bought a new car with 4 of those tires , what is the probability that one of these tires is defective.
\n" ); document.write( "thanks for your help
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Algebra.Com's Answer #194399 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
2% of production is defective.\r
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\n" ); document.write( "\n" ); document.write( "the probability of any tire being defective is 2%.\r
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\n" ); document.write( "\n" ); document.write( "this means that the probability of not getting a defective tire is 98%\r
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\n" ); document.write( "\n" ); document.write( "the probability of getting 0 defective tires out of 4 tires = .98^4 = .92236815.\r
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\n" ); document.write( "\n" ); document.write( "the probability of getting at least 1 defective tire is therefore 1 - .92236815 = .07763184.\r
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\n" ); document.write( "\n" ); document.write( "here's how it works.\r
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\n" ); document.write( "\n" ); document.write( "the probability of getting exactly 0 defective tires is 1 * .98^4 = :
\n" ); document.write( ".92236815.
\n" ); document.write( "the probability of getting exactly 1 defective tire is 4 * .02 * .98^3 = :
\n" ); document.write( ".07529536
\n" ); document.write( "the probability of getting exactly 2 defective tires is 6 * .02^2 * .98^2 = :
\n" ); document.write( ".00230496
\n" ); document.write( "the probability of getting exactly 3 defective tires is 4 * .02^3 * .98 = :
\n" ); document.write( ".00003136
\n" ); document.write( "the probability of getting exactly 4 defective tires is 1 * .02^4 = :
\n" ); document.write( ".00000016\r
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\n" ); document.write( "\n" ); document.write( "sum up all those probabilities and you get 1.\r
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\n" ); document.write( "\n" ); document.write( "this is what you should get.\r
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\n" ); document.write( "\n" ); document.write( "I summed up the numbers stored in the calculator that were not rounded so I got exactly 1. If you add up the displayed numbers, you will get close to 1 but not right on.\r
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\n" ); document.write( "\n" ); document.write( "your answer is:\r
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\n" ); document.write( "\n" ); document.write( "the probability of getting at least 1 defective tire is .07763184.\r
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\n" ); document.write( "\n" ); document.write( "the probability of getting exactly 1 defective tire is .07529536\r
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\n" ); document.write( "\n" ); document.write( "the implicit assumption in all of this is that the manufacturer is making a very large number of tires, so that the probability can be calculated assuming replacement rather than not assuming replacement.\r
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\n" ); document.write( "\n" ); document.write( "the multipliers in each operation are based on combination theory.\r
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\n" ); document.write( "\n" ); document.write( "the possible number of ways of getting a set of 0 out of 4 is 1
\n" ); document.write( "the possible number of ways of getting a set of 1 out of 4 is 4
\n" ); document.write( "the possible number of ways of getting a set of 2 out of 4 is 6
\n" ); document.write( "the possible number of ways of getting a set of 3 out of 4 is 4
\n" ); document.write( "the possible number of ways of getting a set of 4 out of 4 is 1\r
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\n" ); document.write( "\n" ); document.write( "assume your set is abcd.\r
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\n" ); document.write( "\n" ); document.write( "there is only 1 way of getting a set of 0 out of this.
\n" ); document.write( "you just don't draw any.\r
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\n" ); document.write( "\n" ); document.write( "there is 4 ways of getting a set of 1 out of this.
\n" ); document.write( "you can get a, b, c, or d.\r
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\n" ); document.write( "\n" ); document.write( "there is 6 ways of geting a set of 2 out of this.
\n" ); document.write( "you can get ab, ac, ad, bc, bd, cd\r
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\n" ); document.write( "\n" ); document.write( "there is 4 ways of getting a set of 3 out of this.
\n" ); document.write( "you can get abc, abd, acd, bcd\r
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\n" ); document.write( "\n" ); document.write( "there is 1 way of getting a set of 4 out of this.
\n" ); document.write( "you can get abcd only.\r
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\n" ); document.write( "\n" ); document.write( "these are combinations, not permutations. order is not important. abc is considered the same set as acb, bac, bca, cab, cba.\r
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