document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263845>Question 263845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One train leaves City A heading for City B which is 390 miles away. At the same time a secind train leaves City B heading for City A, going 15 mph faster than the first train. If they meet in 3 hours and 20 minutes, how fast are the trains traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194389 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "390=(X+X+15)10/3<BR>\n" );
document.write( "390=(2X+15)10/3<BR>\n" );
document.write( "390=(20X+150)/3<BR>\n" );
document.write( "390*3=20X+150<BR>\n" );
document.write( "20X=1,170-150<BR>\n" );
document.write( "20X=1,020<BR>\n" );
document.write( "X=1,020/20<BR>\n" );
document.write( "X=51 MPH FOR THE SLOWER TRAIN.<BR>\n" );
document.write( "51+15=66 MPH IS THE SPEED OF THE FASTER TRAIN.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "390=(51+66)10/3<BR>\n" );
document.write( "390=117*10/3<BR>\n" );
document.write( "390=1,170/3<BR>\n" );
document.write( "390=390 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );