document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263829>Question 263829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mrs. Huang operates a soybean fam.  She buys many supplies in bulk.  Often the bulk products need to be custom mixed before Mrs. Huang can use them.  To apply herbicide to a large field she must mix a solution of 67% herbicide with a solution of 46% herbicide to form 42 liters of a 55% solution.  How much of the 67% solution must she use?<BR>\n" );
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document.write( "a. 23L   b. 18L  c.  34L  d. 35L<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194382 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 67% solution needed<BR>\n" );
document.write( "Then 42-x=amount of 46% solution needed<BR>\n" );
document.write( "Now we know that the pure herbicide in the 67% solution (0.67x) plus the amount of pure herbicide in the 46% solution (0.46(42-x)) has to equal the amount of pure herbicide in the final mixture (0.55*42).  So, our equation to solve is:\r<BR>\n" );
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document.write( "0.67x+0.46(42-x)=0.55*42  simplify<BR>\n" );
document.write( "0.67x+19.32-0.46x=23.1  subtract 19.32 from each side<BR>\n" );
document.write( "0.67x+19-32-19.32-0.46x=23.1-19.32  collect like terms<BR>\n" );
document.write( "0.21x=3.78  divide each side by 0.21<BR>\n" );
document.write( "x=18 liters------amount of 67% solution needed\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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