document.write( "Question 263784: A man spent 1/3 of his money and then lost 2/3 of the remainder. He was left with $12.00. How much did he start with? \r
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Algebra.Com's Answer #194360 by mananth(16946) $\"\"$ $\"About$

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A man spent 1/3 of his money and then lost 2/3 of the remainder. He was left with $12.00. How much did he start with? \r
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\n" ); document.write( "\n" ); document.write( "assume he $x\r
\n" ); document.write( "\n" ); document.write( "spent 1/3 *x\r
\n" ); document.write( "\n" ); document.write( "lost 2/3 *(x- 1/3*x)\r
\n" ); document.write( "\n" ); document.write( "x- (1/3 *x + 2/3 * (x-1/3) *x)=12\r
\n" ); document.write( "\n" ); document.write( "x- (1/3*x +2/3(3x-x/3)) =12
\n" ); document.write( "x-(1/3 *x +4/9 *x)=12
\n" ); document.write( "x-((3x+4x) / 9)=12
\n" ); document.write( "9x-3x-4x=108
\n" ); document.write( "2x=108
\n" ); document.write( "x=54 He started with $ 54\r
\n" ); document.write( "\n" ); document.write( "spent 1/3 *x= $18\r
\n" ); document.write( "\n" ); document.write( "lost 2/3 *(x- 1/3*x) = 24\r
\n" ); document.write( "\n" ); document.write( "Balance =12 \r
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