document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263782>Question 263782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194359 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers.\r<BR>\n" );
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document.write( "let the second number be x\r<BR>\n" );
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document.write( "third = 10x-11\r<BR>\n" );
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document.write( "first  = (3x+7)/2\r<BR>\n" );
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document.write( "x+10x-11 + (3x+7)/2 = 105\r<BR>\n" );
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document.write( "2x+20x-22+3x+7 = 210\r<BR>\n" );
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document.write( "25x=225x\r<BR>\n" );
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document.write( "x= 9 = second\r<BR>\n" );
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document.write( "third = 79\r<BR>\n" );
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document.write( "first =17<BR>\n" );
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