document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263697>Question 263697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 125^(x+3)=(5^(2x))/(15625) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194358 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 125^(x+3)=(5^(2x))/(15625)\r<BR>\n" );
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document.write( "a^m*a^n=a^(m+n)\r<BR>\n" );
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document.write( "125^x+125^3= 5^2x/ 15625\r<BR>\n" );
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document.write( "(5^3)^x +(5^3)^3 = 5^2x/15625\r<BR>\n" );
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document.write( "5^3x +5^9=5^2x/(25)^3\r<BR>\n" );
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document.write( "5^3x +5^9 = 5^2x / 5^6\r<BR>\n" );
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document.write( "5^3x +5^9 = 5^(2x-6)\r<BR>\n" );
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document.write( "3x+9=2x-6\r<BR>\n" );
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document.write( "x=-15 </SPAN>\n" );
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