document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32997>Question 32997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the length of a rectangle is 2 km longer then twice the width, then what is the length if the area is 60 sqare kilometer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19435 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x<BR>\n" );
document.write( "Let the length be 2x+2<BR>\n" );
document.write( "Area = 60km^2.<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "(x)(2x+2)=60<BR>\n" );
document.write( "2x^2+2x=60<BR>\n" );
document.write( "2x^2+2x-60=0<BR>\n" );
document.write( "x^2+x-30=0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(x-5)(x+6)<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "2(5)+2=12<BR>\n" );
document.write( "Hence, the width is 5km and the length is 12km.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );