document.write( "Question 263743: Given p is true, q is false, and r is true, find the truth value of the statement (~p ^ q) ↔ ~r. \r
\n" ); document.write( "\n" ); document.write( "its true.
\n" ); document.write( "i made a truth table but i think im wrong
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Algebra.Com's Answer #194336 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If p is true, then ~p is false (since ~p is the opposite of p).\r
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\n" ); document.write( "\n" ); document.write( "Remember that \"^\" means \"and\". The statement p ^ q is only true if BOTH p AND q are true (hence the \"and\"). Since ~p is false, we automatically know that ~p ^ q is false (q doesn't have to be factored in at all).\r
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\n" ); document.write( "\n" ); document.write( "Finally, remember that p <-> q is only true if the truth values for p and q are the same. So if p and q are both true, or both false, then p <-> q is true. Think of this as an \"equals\" (ie p = q). Because r is true, ~r is false. Since ~p ^ q is false as well, ~p ^ q and ~r have the same truth values. So (~p ^ q) <-> ~r is true. So you are correct. Good job.\r
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\n" ); document.write( "\n" ); document.write( "Here's one way you could write all this out:\r
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\n" ); document.write( "\n" ); document.write( "(~p ^ q) <-> ~r\r
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\n" ); document.write( "\n" ); document.write( "(~T ^ F) <-> ~T\r
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\n" ); document.write( "\n" ); document.write( "(F ^ F) <-> F\r
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\n" ); document.write( "\n" ); document.write( "F <-> F\r
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