document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263730>Question 263730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The sum of the measure of the first angle and one- fourth the second  angle is 82.5 degree. Find the measures of  the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194332 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The sum of the measure of the first angle and one- fourth the second  angle is 82.5 degree. Find the measures of  the angles.\r<BR>\n" );
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document.write( "Let one angle be x\r<BR>\n" );
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document.write( "The other angle will be 90-x\r<BR>\n" );
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document.write( "X+1/4(90-x)= 82.5  Take LCD on the fractions\r<BR>\n" );
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document.write( "4x+90 –x= 4*82.5<BR>\n" );
document.write( "3x= 330-90<BR>\n" );
document.write( "X=240/3 = 80\r<BR>\n" );
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document.write( "So other angle = 10<BR>\n" );
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