document.write( "Question 263708: A man has 15 coins in his pocket, all of which are dimes and quarters. If the total value of his change is $2.75, how many dimes and how many quarters does he have?
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Algebra.Com's Answer #194321 by richwmiller(17219)\"\" \"About 
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d+q=15
\n" ); document.write( "10d+25q=275
\n" ); document.write( "d=15-q
\n" ); document.write( "10(15-q)+25q=275
\n" ); document.write( "150-10q+25q=275
\n" ); document.write( "15q=125
\n" ); document.write( "q=125/15=25/3
\n" ); document.write( "we can't have fractional amount for number of coins.
\n" ); document.write( "q=15-d
\n" ); document.write( "10d+25(15-d)=275
\n" ); document.write( "2d+5(15-d)=55
\n" ); document.write( "2d+75-5d=55
\n" ); document.write( "-3d=-20
\n" ); document.write( "d=20/3
\n" ); document.write( "again we can't have a fractional number of coins.
\n" ); document.write( "Something is wrong with the problem
\n" ); document.write( "either 15 is wrong or 275 is wrong\r
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