document.write( "Question 263609: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol? \n" ); document.write( "
Algebra.Com's Answer #194316 by ankor@dixie-net.com(22740)\"\" \"About 
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How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol?
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\n" ); document.write( "let x = amt of 40% solution required
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\n" ); document.write( "A typical mixture equation
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\n" ); document.write( ".4x + .8(10) = .60(x+10)
\n" ); document.write( ".4x + 8 = .6x + 6
\n" ); document.write( "8 - 6 = .6x - .4x
\n" ); document.write( "2 = .2x
\n" ); document.write( "x = \"2%2F.2\"
\n" ); document.write( "x = 10 liters of 40% solution required
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\n" ); document.write( "Check
\n" ); document.write( " .4(10) + .8(10) = .6(10+10)
\n" ); document.write( "4 + 8 = .6(20)
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