document.write( "Question 263609: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol? \n" ); document.write( "
Algebra.Com's Answer #194316 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol? \n" ); document.write( ": \n" ); document.write( "let x = amt of 40% solution required \n" ); document.write( ": \n" ); document.write( "A typical mixture equation \n" ); document.write( ": \n" ); document.write( ".4x + .8(10) = .60(x+10) \n" ); document.write( ".4x + 8 = .6x + 6 \n" ); document.write( "8 - 6 = .6x - .4x \n" ); document.write( "2 = .2x \n" ); document.write( "x = \n" ); document.write( "x = 10 liters of 40% solution required \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check \n" ); document.write( " .4(10) + .8(10) = .6(10+10) \n" ); document.write( "4 + 8 = .6(20) \n" ); document.write( " |