document.write( "Question 263644: one number is twice another number. If the larger is diminished by ten the result is two more than the smaller. Find the number. \n" ); document.write( "
Algebra.Com's Answer #194288 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! x is one number. \n" ); document.write( "y is another. \n" ); document.write( "We are told: y = 2x. \n" ); document.write( "And we are told: y-10 = x+2 \n" ); document.write( ". \n" ); document.write( "So, we have two definitions of y: \n" ); document.write( "y = 2x \n" ); document.write( "and \n" ); document.write( "y-10 = x+2 \n" ); document.write( "y = x+12 \n" ); document.write( "Since the identity y=y is obvious, then we can say \n" ); document.write( "2x = x+12 \n" ); document.write( ". \n" ); document.write( "Subtracting x from both sides \n" ); document.write( "x = 12 \n" ); document.write( ". \n" ); document.write( "In our set up we defined: y = 2x, so y = 2*12 = 24 \n" ); document.write( ". \n" ); document.write( "We can check by substituting these values into the other equation we defined: \n" ); document.write( "y-10 = 14 \n" ); document.write( "Does this = 12+2? \n" ); document.write( "Yes it does. \n" ); document.write( ". \n" ); document.write( "So, the two values are: 12 and 24. \n" ); document.write( " |