document.write( "Question 32975This question is from textbook algebra for college students
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document.write( ":  Can anybody help me with this problem? I'm trying to teach this stuff to myself and am having trouble grasping logarithmic functions. Thanks. \r
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document.write( "log(x)- log(3)= log(6) \n" );
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| Algebra.Com's Answer #19425 by sarah_adam(201)      You can put this solution on YOUR website! \n" ); document.write( "log(x)- log(3)= log(6) \n" ); document.write( "log(x) = log(6)+log(3) \n" ); document.write( "log(x) = log(6*3) as log a + log b = log(a*b) \n" ); document.write( "log(x) = log(18) \n" ); document.write( "x = 18 \n" ); document.write( " \n" ); document.write( " |