document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263564>Question 263564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ellen wishes to mix candy worth $1.80 per pound with candy worth $2.40 per pound to form 48 pounds of a mixture worth $2.00 per pound. How many pounds of the more expensive candy should she use?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194222 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194222\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ellen wishes to mix candy worth $1.80 per pound with candy worth $2.40 per pound to form 48 pounds of a mixture worth $2.00 per pound. How many pounds of the more expensive candy should she use? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "1.8x + 2.4(48-x) = 2*48<BR>\n" );
document.write( "Multiply thru by 10 to get:<BR>\n" );
document.write( "18x + 24*48 - 24x = 20*48<BR>\n" );
document.write( "-6x = -4*48<BR>\n" );
document.write( "x = 4*8 = 32 (amount of $1.80 candy needed in the mixture)<BR>\n" );
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document.write( "48-32 = 16 lbs (amount of $2.40 candy needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );