document.write( "Question 263512: If a pharmacist wants to make 150 milliliters of a 20 percent alcohol solution, but only has a 30 percent alcohol solution and a 15 percent alcohol solution, how much of each solution should she mix together to get what she needs?
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document.write( "Could you please take me step by step? \n" );
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Algebra.Com's Answer #194191 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! When solving a solution problem, you have to determine how much of the 'pure' stuff you need in the solution. \n" ); document.write( "In this case, you need 150 ml of 20% alcohol. \n" ); document.write( "That means there will be 30 ml of alcohol and 120 ml of water. \n" ); document.write( "Using the 30% solution, how much would you need to have 30 ml of pure 'alcohol'? \n" ); document.write( "30 ml = .3x \n" ); document.write( ".3x = 30 \n" ); document.write( "x = 100 ml \n" ); document.write( "That is, if you have 100 ml of 30% alcohol solution, then you have 30 ml of alcohol and 70 ml of water. \n" ); document.write( "So, measure our 100 ml of the 30% alcohol solution and add 50 ml of pure water. \n" ); document.write( "You now will have a total volume of 150 ml, of which, 30 ml are pure alcohol. \n" ); document.write( "30/150 = .2 \n" ); document.write( "which means you have your required 150 ml of 20% alcohol solution. \n" ); document.write( ". \n" ); document.write( "Unless you're required to use the 15% alcohol solution, why bother with it at all? Just dilute the 30% solution and you're done. \n" ); document.write( ". \n" ); document.write( "But teachers can be picky... \n" ); document.write( ". \n" ); document.write( "So another way to look at the problem is to think in terms any other word problem. \n" ); document.write( "You need to mix a 30% solution and a 15% solution to arrive at a 20% solution. \n" ); document.write( "We know the final result is supposed to be 150 ml of 20% solution, which we can show as .2*150. \n" ); document.write( "If we use 'x' amount of the 30% solution, then we are forced to use 150-x of the 15% solution. \n" ); document.write( "That defines an equation: \n" ); document.write( ".3x + .15(150-x) = .2(150) \n" ); document.write( ".3x + 22.5 - .15x = 30 \n" ); document.write( ".3x - .15x = 30 - 22.5 \n" ); document.write( ".15x = 7.5 \n" ); document.write( "x = 50 \n" ); document.write( "So you use 50 ml of the 30% solution and 150-50 = 100 ml of the 15% solution. \n" ); document.write( "Check this by determining how much 'pure stuff' is in the final solution. \n" ); document.write( ".15*100 = 15 \n" ); document.write( ".3*50 = 15 \n" ); document.write( "total = 30 ml of pure alcohol in the 150 ml \n" ); document.write( ". \n" ); document.write( " |