document.write( "Question 263481: a coin bank containe nickels, dimes, and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank? \n" ); document.write( "
Algebra.Com's Answer #194160 by checkley77(12844)\"\" \"About 
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Q=2D OR D=Q/2
\n" ); document.write( "N=Q+11
\n" ); document.write( "N+D+Q=5.45
\n" ); document.write( ".05N+.10D+.25Q=5.45
\n" ); document.write( ".05(Q+11)+.10(Q/2)+.25Q=5.45
\n" ); document.write( ".05Q+.55+.05Q+.25Q=5.45
\n" ); document.write( ".35Q=5.45-.55
\n" ); document.write( ".35Q=4.90
\n" ); document.write( "Q=4.90/.35
\n" ); document.write( "Q=14 QUARTERS.
\n" ); document.write( "N=14+11=25 NICKELS
\n" ); document.write( "D=14/2=7 DIMES
\n" ); document.write( "PROOF:
\n" ); document.write( ".05*25+.10*7+.25*14=5.45
\n" ); document.write( "1.25+.70+3.50=5.45
\n" ); document.write( "5.45=5.45
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