document.write( "Question 263481: a coin bank containe nickels, dimes, and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank? \n" ); document.write( "
Algebra.Com's Answer #194160 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Q=2D OR D=Q/2 \n" ); document.write( "N=Q+11 \n" ); document.write( "N+D+Q=5.45 \n" ); document.write( ".05N+.10D+.25Q=5.45 \n" ); document.write( ".05(Q+11)+.10(Q/2)+.25Q=5.45 \n" ); document.write( ".05Q+.55+.05Q+.25Q=5.45 \n" ); document.write( ".35Q=5.45-.55 \n" ); document.write( ".35Q=4.90 \n" ); document.write( "Q=4.90/.35 \n" ); document.write( "Q=14 QUARTERS. \n" ); document.write( "N=14+11=25 NICKELS \n" ); document.write( "D=14/2=7 DIMES \n" ); document.write( "PROOF: \n" ); document.write( ".05*25+.10*7+.25*14=5.45 \n" ); document.write( "1.25+.70+3.50=5.45 \n" ); document.write( "5.45=5.45 \n" ); document.write( " \n" ); document.write( " |