document.write( "Question 263439: please help me solve this equation :) \r
\n" ); document.write( "\n" ); document.write( "abs(x+3) = abs(2x+1)
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Algebra.Com's Answer #194140 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
Here is the original question
\n" ); document.write( "\"abs%28x%2B3%29+=+abs%282x%2B1%29\"
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\n" ); document.write( "this will be a bit tricky in that that we have 3 equations to solve.
\n" ); document.write( "equation #1:
\n" ); document.write( "x+3 = 2x+1
\n" ); document.write( "step 1 - subtract x and subtract 1 to get
\n" ); document.write( "2 = x
\n" ); document.write( "-----
\n" ); document.write( "equation #2:
\n" ); document.write( "x+3 = -(2x+1)
\n" ); document.write( "step 1 - distribute the - through to get
\n" ); document.write( "x+3 = -2x -1
\n" ); document.write( "step 2 - add 2x and subtract 3 to get
\n" ); document.write( "3x = -4
\n" ); document.write( "step 3 - divide to get
\n" ); document.write( " x = -4/3
\n" ); document.write( "-----
\n" ); document.write( "equation #3:
\n" ); document.write( "2x+1 = -(x+3)
\n" ); document.write( "step 1 - distribute the - through to get
\n" ); document.write( "2x + 1 = -x -3
\n" ); document.write( "step 2 - add x and subtract 1 to get
\n" ); document.write( "3x = -4
\n" ); document.write( "step 3 - divide to get
\n" ); document.write( " x = -4/3
\n" ); document.write( "----
\n" ); document.write( "so it appears that our answers are
\n" ); document.write( " x = -4/3, 2
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\n" ); document.write( "here are the graphs
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+10%2C+abs%28x%2B3%29%2C+abs%282x%2B1%29%29+\"
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