document.write( "Question 263379: Mean: 1.31
\n" );
document.write( "Standard deviation: 0.04
\n" );
document.write( "random Sample: 16\r
\n" );
document.write( "\n" );
document.write( "What is the probablity that the sample is between 1.28 and 1.32 \n" );
document.write( "
Algebra.Com's Answer #194115 by stanbon(75887) ![]() You can put this solution on YOUR website! Mean: 1.31 \n" ); document.write( "Standard deviation: 0.04 \n" ); document.write( "random Sample: 16 \n" ); document.write( "What is the probablity that the sample is between 1.28 and 1.32 \n" ); document.write( "------------------- \n" ); document.write( "t(1.28) = (1.28-1.31)/[0.04/sqrt(16)] = -3 \n" ); document.write( "t(1.32) = (1.32-1.31)/[0.04/sqrt(16)] = 1 \n" ); document.write( "--- \n" ); document.write( "P(1.28< x < 1.32) = P(-3< t < 1 when df = 15) = 0.8289.. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |