document.write( "Question 263393: An 8 hp pump can fill a tank in 8 hours. A smaller 3 hp pump fills the same tank in 12 hours. The pumps are used together to begin filling this tank. After four hours, the 8 hp pump breaks down. How long will it take the smaller pump to fill the tank? \n" ); document.write( "
Algebra.Com's Answer #194114 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
This is a working together problem.
\n" ); document.write( "The rate of the 8 hp pump = 1/8
\n" ); document.write( "the rate of the 3 hp pump is 1/12
\n" ); document.write( "The time together will be 4 hours.
\n" ); document.write( "The time that the 3 hp pump works alone is x hrs.
\n" ); document.write( "We want to fill only 1 tank
\n" ); document.write( "-----
\n" ); document.write( "we use the formula
\n" ); document.write( "\"%281%2F8%29%2A4+%2B+%281%2F12%29%2A4+%2B+%281%2F12%29%2Ax+=+1\"
\n" ); document.write( "we get
\n" ); document.write( "\"4%2F8+%2B+4%2F12+%2B+x%2F12+=+1\"
\n" ); document.write( "adding the fractions, we get
\n" ); document.write( "\"+5%2F6+%2B+x%2F12+=+1\"
\n" ); document.write( "subtract 5/6 to get
\n" ); document.write( " \"x%2F12+=+1%2F6\"
\n" ); document.write( "multiply by 12 to get
\n" ); document.write( " \"x+=+2\"
\n" ); document.write( "So, the 3 hp pump must work and additional 2 hours.
\n" ); document.write( "
\n" );