document.write( "Question 263397: cant seem to solve this one.. i have to put it on a number line too\r
\n" ); document.write( "\n" ); document.write( "x^2 + 2x > 3\r
\n" ); document.write( "\n" ); document.write( "Thanks! \n" ); document.write( "

Algebra.Com's Answer #194099 by drk(1908) $\"\"$ $\"About$

You can put this solution on YOUR website!
here is the original question
\n" ); document.write( " $\"x%5E2+%2B+2x+%3E+3\"$
\n" ); document.write( "step 1 - subtract 3 to get
\n" ); document.write( " $\"x%5E2%2B2x+-+3+%3E+0\"$
\n" ); document.write( "step 2 -factor to get
\n" ); document.write( " $\"%28x%2B3%29%28x-1%29+%3E+0\"$
\n" ); document.write( "step 3 we need to create 3 number line graphs. Make sure the 0 marker is aligned in all three.
\n" ); document.write( "number line graph #1:
\n" ); document.write( "x+3> 0
\n" ); document.write( "this means open circle above -3 and then + signs to the right and - signs to the left.
\n" ); document.write( "number line graph #2:
\n" ); document.write( "x-1> 0
\n" ); document.write( "this means open circle above +1 and then + signs to the right and - signs to the left.
\n" ); document.write( "number line graph #3:
\n" ); document.write( "(x+3)(x-1) > 0
\n" ); document.write( "we place open circles above -3 and then +1.
\n" ); document.write( "To the left of -3, we have - signs for both lines. - x - = + so in the third number line place a + to the left of -3.
\n" ); document.write( "Between -3 and +1 we have different signs, so place a - sign on the third number line between -3 and +1.
\n" ); document.write( "To the right of +1, we have + signs for both lines. + x + = +, so in the third number line place a + to the right of +1.
\n" ); document.write( "we want where the signs are > 0 or the + regions.
\n" ); document.write( "Our final answer is
\n" ); document.write( "open circles above -3 and +1 and then arrow from the -3 to the left and arrow from the +1 to the right. \n" ); document.write( "

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