document.write( "Question 263378: Verify that -2 is a root of the equation \"2x%5E3%2Bx%5E2-10x-8=0\"
\n" ); document.write( "Find the other two roots, correct to 2 decimal places.
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Algebra.Com's Answer #194089 by drk(1908)\"\" \"About 
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we can use synthetic division to verify. This will generate another equation that we will factor.\r
\n" ); document.write( "\n" ); document.write( "-2 // . . . 2 . . . . 1 . . . . -10 . . . . . -8
\n" ); document.write( " . . . . . . . . . . . . -4 . . . . .6 . . . . . . .8
\n" ); document.write( " . . . . . . . 2 . . . . -3 . . . . -4 . . . // . 0\r
\n" ); document.write( "\n" ); document.write( "So, we have verified by getting a 0 remainder. We now have a new equation of the form
\n" ); document.write( "\"2x%5E2+-+3x+-+4+=+0\"
\n" ); document.write( "By quadratic, we get
\n" ); document.write( "\"x+=+%283+%2B-+sqrt%289-4%2A2%2A%28-4%29%29%29%2F%284%29\"
\n" ); document.write( "and then
\n" ); document.write( "\"x+=+%283+%2B-+sqrt%2841%29%29%2F%284%29\"
\n" ); document.write( "we have two answers and rounded, we get
\n" ); document.write( " x ~ 2.35
\n" ); document.write( "x ~ -0.85
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