document.write( "Question 263346: I am stumped on this question and I am not sure how to figure out the perimeter. If I knew that number I could solve the problem. Thanks for your help.\r
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document.write( "Consider a square and a regular hexagon (a six sided figure with sides of equal length). One side of the square is 7 feet longer than a side of the hexagon, and the two figures have the same perimeter. What are the lengths of the sides of each figure?\r
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document.write( "I set it up as x= hexagon
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document.write( " x+7= square\r
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document.write( "x+x+7=? \n" );
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Algebra.Com's Answer #194074 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! The trick is to find the sides then find the perimeter not the perimeter first. \n" ); document.write( "We know that \n" ); document.write( "the side nof the square is 7 more than the side of the hexagon \n" ); document.write( "s=h+7 and \n" ); document.write( "and we know that the perimeter of the square is 4s \n" ); document.write( "and the hexagon is 6h \n" ); document.write( "and the the two perimeters are equal \n" ); document.write( "4s=6h \n" ); document.write( "s=h+7 \n" ); document.write( "substitute h+7 for s \n" ); document.write( "4(h+7)=6h \n" ); document.write( "4h+28=6h \n" ); document.write( "28=2h \n" ); document.write( "14=h \n" ); document.write( "s=h+7 \n" ); document.write( "s=21 \n" ); document.write( "h=14 s=21 \n" ); document.write( "check \n" ); document.write( "6*14=4*21 \n" ); document.write( "84=84 \n" ); document.write( "both perimeters equal 84 \n" ); document.write( "ok \n" ); document.write( "This problem should be in the word problem geometry category \n" ); document.write( " |