document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32957>Question 32957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of each side of the rectangle so that it has the given perimeter\r<BR>\n" );
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document.write( "Long side 2x - 5 short side x P= 50\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19405 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2(L+W) where L = length and W = width<BR>\n" );
document.write( "here let L = (2x-5) where x = shorter side<BR>\n" );
document.write( "P = 2(2x- 5 +x)<BR>\n" );
document.write( "50 = 2 (3x - 5)<BR>\n" );
document.write( "25 = 3x - 5<BR>\n" );
document.write( "3x = 30<BR>\n" );
document.write( "x = 10ft<BR>\n" );
document.write( "Longer side = 2x - 5 = 2(10) - 5 = 20 -5 = 15 ft </SPAN>\n" );
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