document.write( "Question 263310: The table shows the relationship between x and y in a quadratic equation of the form y = ax^2 + bx + c, where a, b, and c are integers.What is the value of a?\r
\n" ); document.write( "\n" ); document.write( "x 1 2 3 4 5 6 7 \r
\n" ); document.write( "\n" ); document.write( "y -8 5 24 49 80 117 160
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Algebra.Com's Answer #194037 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
x=1 y=-8
\n" ); document.write( "ax^2+bx+c=y\r
\n" ); document.write( "\n" ); document.write( "c = -a-b-8, x = 1, y = -8
\n" ); document.write( "c = -4 a-2 b+5, x = 2, y = 5
\n" ); document.write( "c = -3 (3 a+b-8), x = 3, y = 24
\n" ); document.write( "c = -16 a-4 b+49, x = 4, y = 49
\n" ); document.write( "c = -a-b-8 and
\n" ); document.write( "c = -4a-2 b+5 and
\n" ); document.write( "c = -3*(3a+b-8) and
\n" ); document.write( "c = -16a-4b+49\r
\n" ); document.write( "\n" ); document.write( "a = 3, b = 4, c = -15
\n" ); document.write( "y=3x^2+4x-15
\n" ); document.write( "y=(x+3)(3x-5)
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Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression \"3x%5E2%2B4x-15\", we can see that the first coefficient is \"3\", the second coefficient is \"4\", and the last term is \"-15\".



Now multiply the first coefficient \"3\" by the last term \"-15\" to get \"%283%29%28-15%29=-45\".



Now the question is: what two whole numbers multiply to \"-45\" (the previous product) and add to the second coefficient \"4\"?



To find these two numbers, we need to list all of the factors of \"-45\" (the previous product).



Factors of \"-45\":

1,3,5,9,15,45

-1,-3,-5,-9,-15,-45



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to \"-45\".

1*(-45) = -45
3*(-15) = -45
5*(-9) = -45
(-1)*(45) = -45
(-3)*(15) = -45
(-5)*(9) = -45


Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"4\":



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First NumberSecond NumberSum
1-451+(-45)=-44
3-153+(-15)=-12
5-95+(-9)=-4
-145-1+45=44
-315-3+15=12
-59-5+9=4




From the table, we can see that the two numbers \"-5\" and \"9\" add to \"4\" (the middle coefficient).



So the two numbers \"-5\" and \"9\" both multiply to \"-45\" and add to \"4\"



Now replace the middle term \"4x\" with \"-5x%2B9x\". Remember, \"-5\" and \"9\" add to \"4\". So this shows us that \"-5x%2B9x=4x\".



\"3x%5E2%2Bhighlight%28-5x%2B9x%29-15\" Replace the second term \"4x\" with \"-5x%2B9x\".



\"%283x%5E2-5x%29%2B%289x-15%29\" Group the terms into two pairs.



\"x%283x-5%29%2B%289x-15%29\" Factor out the GCF \"x\" from the first group.



\"x%283x-5%29%2B3%283x-5%29\" Factor out \"3\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



\"%28x%2B3%29%283x-5%29\" Combine like terms. Or factor out the common term \"3x-5\"



===============================================================



Answer:



So \"3%2Ax%5E2%2B4%2Ax-15\" factors to \"%28x%2B3%29%283x-5%29\".



In other words, \"3%2Ax%5E2%2B4%2Ax-15=%28x%2B3%29%283x-5%29\".



Note: you can check the answer by expanding \"%28x%2B3%29%283x-5%29\" to get \"3%2Ax%5E2%2B4%2Ax-15\" or by graphing the original expression and the answer (the two graphs should be identical).


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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"3x%5E2%2B4x%2B-15+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%284%29%5E2-4%2A3%2A-15=196\".
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\n" ); document.write( " Discriminant d=196 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-4%2B-sqrt%28+196+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%284%29%2Bsqrt%28+196+%29%29%2F2%5C3+=+1.66666666666667\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%284%29-sqrt%28+196+%29%29%2F2%5C3+=+-3\"
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\n" ); document.write( " Quadratic expression \"3x%5E2%2B4x%2B-15\" can be factored:
\n" ); document.write( " \"3x%5E2%2B4x%2B-15+=+3%28x-1.66666666666667%29%2A%28x--3%29\"
\n" ); document.write( " Again, the answer is: 1.66666666666667, -3.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B4%2Ax%2B-15+%29\"
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