document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263249>Question 263249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i cant figure out how to correctly form an equation for this:\r<BR>\n" );
document.write( "\n" );
document.write( "a cyclist leaves his training base for a morning workout riding at a rate of 18mph. one hour later, is support staff leaves the base in a car going 45mph in the same direction. how long will it take the support staff o catch up with the cyclist?\r<BR>\n" );
document.write( "\n" );
document.write( "thanks for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193989 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a cyclist leaves his training base for a morning workout riding at a rate of 18mph. one hour later, is support staff leaves the base in a car going 45mph in the same direction. how long will it take the support staff o catch up with the cyclist? <BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let t = hours it takes staff to catch up<BR>\n" );
document.write( "then<BR>\n" );
document.write( "\"cyclist distance traveled\" = \"distance staff traveled\"<BR>\n" );
document.write( "(t+1)18 = t(45)<BR>\n" );
document.write( "18t+18 = 45t<BR>\n" );
document.write( "18 = 27t<BR>\n" );
document.write( "18/27 = t<BR>\n" );
document.write( "2/3 hours = t<BR>\n" );
document.write( "or<BR>\n" );
document.write( "40 minutes = t<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );