document.write( "Question 262187: When 100 is divided by some positive integer x, the remainder is 10.
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Algebra.Com's Answer #193980 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "In order to leave a remainder of 10, the\r\n" );
document.write( "division must look like this:\r\n" );
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document.write( "     Q\r\n" );
document.write( " x)100\r\n" );
document.write( "    90\r\n" );
document.write( "    10\r\n" );
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document.write( "So x must be an integer greater than the remainder 10.\r\n" );
document.write( "Also in order to leave a 10 remainder, the integer \r\n" );
document.write( "quotient times the divisor, x, must equal to 90.  \r\n" );
document.write( "Therefore we have a case of this for every way \r\n" );
document.write( "we can break 90 into two factors x and Q, with x \r\n" );
document.write( "being greater than 10.  There are 5 such ways:\r\n" );
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document.write( "x*Q = 15*6, 18*5, 30*3, 45*2, 90*1   \r\n" );
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document.write( "The sum of the smallest and largest values of x is\r\n" );
document.write( "15+90 or 105.\r\n" );
document.write( "\r\n" );
document.write( "     6\r\n" );
document.write( "15)100\r\n" );
document.write( "    90\r\n" );
document.write( "    10\r\n" );
document.write( "\r\n" );
document.write( "     5\r\n" );
document.write( "18)100\r\n" );
document.write( "    90\r\n" );
document.write( "    10\r\n" );
document.write( "\r\n" );
document.write( "     3\r\n" );
document.write( "30)100\r\n" );
document.write( "    90\r\n" );
document.write( "    10\r\n" );
document.write( "\r\n" );
document.write( "     2\r\n" );
document.write( "45)100\r\n" );
document.write( "    90\r\n" );
document.write( "    10\r\n" );
document.write( "\r\n" );
document.write( "     1\r\n" );
document.write( "90)100\r\n" );
document.write( "    90\r\n" );
document.write( "    10\r\n" );
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document.write( "Edwin
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