document.write( "Question 263218: How many ounces of a 50 percent alcohol solution must be mixed with 80 ounces of a 20 percent alcohol solution to make a 40 percent alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #193975 by stanbon(75887)\"\" \"About 
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How many ounces of a 50 percent alcohol solution must be mixed with 80 ounces of a 20 percent alcohol solution to make a 40 percent alcohol solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.20*80 + 0.50x = 0.40(80+x)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "20*80 + 50x = 40*80 + 40x
\n" ); document.write( "10x = 20*80
\n" ); document.write( "x = 2*80
\n" ); document.write( "x = 160 ounces (amt. of 50% solution needed for the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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