document.write( "Question 263183: use the quadratic formula to solve this equation
\n" ); document.write( "2x^2-3x=-7
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Algebra.Com's Answer #193945 by drk(1908)\"\" \"About 
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step 1 - set = 0 as follows:
\n" ); document.write( "\"2x%5E2-3x+%2B+7+=+0\"
\n" ); document.write( "step 2 - using quadratic formula, we get
\n" ); document.write( "\"x+=+%283+%2B-+sqrt%289-4%2A2%2A7+%29%29%2F%284%29\"
\n" ); document.write( "and then
\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28-47%29%29%2F%284%29\"
\n" ); document.write( "which gives us the following imaginary roots:
\n" ); document.write( "\"x+=+%283+%2B-+isqrt%2847%29%29%2F%284%29\"
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