document.write( "Question 263127: The speed of a stream is 4 mph. A boat travels 7 miles upstream in the same time it takes to travel 15 miles downstream. What is the speed of the boat in still water?
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Algebra.Com's Answer #193881 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT OR T=D/R \n" ); document.write( "TU=7/(R-C) TRAVEL UPSTREAM \n" ); document.write( "TD=15/(R+C) TRAVEL DOWN STREAM. \n" ); document.write( "THE TIMES ARE EQUAL. \n" ); document.write( "7/(R-4)=15/(R+4) CROSS MULTIPLY. \n" ); document.write( "15(R-4)=7(R+4) \n" ); document.write( "15R-60=7R+28 \n" ); document.write( "15R-7R=28+60 \n" ); document.write( "8R=88 \n" ); document.write( "R=88/8 \n" ); document.write( "R=11 IS THE SPEED OF THE BOAT IN STILL WATER. \n" ); document.write( "PROOF: \n" ); document.write( "7/(11-4)=15(11+4) \n" ); document.write( "7/7=15/15 \n" ); document.write( "1=1 \n" ); document.write( " \n" ); document.write( " |