document.write( "Question 263127: The speed of a stream is 4 mph. A boat travels 7 miles upstream in the same time it takes to travel 15 miles downstream. What is the speed of the boat in still water?
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Algebra.Com's Answer #193875 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
This is an RTD question. Here is a table based on the given information:
\n" ); document.write( "up/down . . . . . . . . . . .rate . . . . . . . . . . .time . . . . . . . . . .distnace
\n" ); document.write( "upstream . . . . . . . . . . r-4 . . . . . . . . . . T . . . . . . . . . . . . . . 7
\n" ); document.write( "downstream . . . . . . . . r+4 . . . . . . . . . . T . . . . . . . . . . . . . . .15
\n" ); document.write( "Now, rate x time = distance, so
\n" ); document.write( "time = distance / rate.
\n" ); document.write( "solve each for T and we get
\n" ); document.write( "T = (7/(r-4))
\n" ); document.write( "T = (15/(r+4))
\n" ); document.write( "set the times equal and we get
\n" ); document.write( "\"7%2F%28r-4%29+=+15%2F%28r%2B4%29\"
\n" ); document.write( "cross multiply to get
\n" ); document.write( "\"7r+%2B+28+=+15r+-+60\"
\n" ); document.write( "subtract 7r to get
\n" ); document.write( " \"28+=+8r+-+60\"
\n" ); document.write( "add 60 to both sides to get
\n" ); document.write( "\"88+=+8r\"
\n" ); document.write( "divide by 8 to get
\n" ); document.write( "\"r+=+8\"
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