document.write( "Question 263127: The speed of a stream is 4 mph. A boat travels 7 miles upstream in the same time it takes to travel 15 miles downstream. What is the speed of the boat in still water?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #193875 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! This is an RTD question. Here is a table based on the given information: \n" ); document.write( "up/down . . . . . . . . . . .rate . . . . . . . . . . .time . . . . . . . . . .distnace \n" ); document.write( "upstream . . . . . . . . . . r-4 . . . . . . . . . . T . . . . . . . . . . . . . . 7 \n" ); document.write( "downstream . . . . . . . . r+4 . . . . . . . . . . T . . . . . . . . . . . . . . .15 \n" ); document.write( "Now, rate x time = distance, so \n" ); document.write( "time = distance / rate. \n" ); document.write( "solve each for T and we get \n" ); document.write( "T = (7/(r-4)) \n" ); document.write( "T = (15/(r+4)) \n" ); document.write( "set the times equal and we get \n" ); document.write( " \n" ); document.write( "cross multiply to get \n" ); document.write( " \n" ); document.write( "subtract 7r to get \n" ); document.write( " \n" ); document.write( "add 60 to both sides to get \n" ); document.write( " \n" ); document.write( "divide by 8 to get \n" ); document.write( " |