document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32668>Question 32668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I dont understand\r<BR>\n" );
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document.write( "1.10^t = 1.4641  (1.10to the power of t (^=power of)) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19387 by </B><A HREF=/tutors/aboutme.mpl?userid=kietra><B>kietra(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kietra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem uses a variable in an equation so the easier way to solve would be using logarithms.  So, your equation1.1^t=1.4641 the first thing to do would be to take the log of both sides. log (1.1^t)= log(1.4641).  Then, using the law of logs, we can take the exponent (t) in front of the log so now t(log 1.1) = log (1.4641).  We want to isolate the variable next so divide log1.1 on both sides so t = (log1.4641)/(log1.1).  Punch those in your calculator log 1.4641=.1655707 (approx) and log(1.1)=.0412937.  Divide those two numbers (.1655707)/(.0412937) and t=4.  If you check your problem, (1.1)^4=1.4641. Yep, it checks.  Here's the problem again without the explanation:\r<BR>\n" );
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document.write( "1.1^t=1.4641<BR>\n" );
document.write( "log (1.1^t)= log(1.4641)<BR>\n" );
document.write( "t(log 1.1) = log (1.4641)<BR>\n" );
document.write( "t = (log1.4641)/(log1.1)<BR>\n" );
document.write( "t = (.1655707)/(.0412937)<BR>\n" );
document.write( "t = 4\r<BR>\n" );
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