document.write( "Question 263045: Totally lost on this. Assume that the mean systolic blood pressure of normal
\n" ); document.write( "adults is 120 mmHg and the standard deviation is 5.6. Assume a normal distribution. Thats one part\r
\n" ); document.write( "\n" ); document.write( "Then they are asking if an individual is selected find the probability that the indivdual's pressure will be between 120 and 121.8 mmhg.\r
\n" ); document.write( "\n" ); document.write( "Any clarification for these would be great. Thanks for all your help
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Algebra.Com's Answer #193863 by stanbon(75887)\"\" \"About 
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Assume that the mean systolic blood pressure of normal
\n" ); document.write( "adults is 120 mmHg and the standard deviation is 5.6.
\n" ); document.write( "Assume a normal distribution. Thats one part.
\n" ); document.write( "Then they are asking if an individual is selected find the probability that the indivdual's pressure will be between 120 and 121.8 mmhg.
\n" ); document.write( "-----------------------
\n" ); document.write( "Find the z-value of 120 and of 121.8
\n" ); document.write( "z(120) = (120-120)/5.6 = 0
\n" ); document.write( "z(121.8) = (121.8-120)/5.6 = 1.8/5.6 = 0.3214..
\n" ); document.write( "-------------------------------------------------
\n" ); document.write( "P(120<= x <=121.8) = P(0<= z <=0.3214) = 0.1260,,
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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