document.write( "Question 263103: a rectangle is twice as long as it is wide. the perimeter is 60 feet. find the dimensions \n" ); document.write( "

Algebra.Com's Answer #193861 by drk(1908) $\"\"$ $\"About$

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a rectangle is twice as long as it is wide
\n" ); document.write( "translates as
\n" ); document.write( "(i) $\"W+=+2L\"$
\n" ); document.write( "the perimeter is 60 feet
\n" ); document.write( "translates as
\n" ); document.write( "(ii) $\"60+=+2L+%2B+2W\"$
\n" ); document.write( "by substitution we get
\n" ); document.write( "(iii) $\"60+=+2L+%2B+2%282L%29\"$
\n" ); document.write( "solving for L, we get
\n" ); document.write( "(Iv) $\"60+=+6L\"$
\n" ); document.write( "and L = 10 ft
\n" ); document.write( "So W = 20 ft \n" ); document.write( "

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