document.write( "Question 263070: SOLVE BY ELIMINATION METHOD\r
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document.write( "5R-4S=-17
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document.write( "4R+5S=52 \n" );
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Algebra.Com's Answer #193856 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! 1.) 5R-4S=-17 \n" ); document.write( "2.) 4R+5S=52\r \n" ); document.write( "\n" ); document.write( "We need to multiply both sides of each of the equations by values that will produce a common coefficient on either x or y in both equations so that when the equations are either added together or subtracted one of the variables is eliminated:\r \n" ); document.write( "\n" ); document.write( "We can eliminate R by multiplying the first equation by 4 and the second equation by 5:\r \n" ); document.write( "\n" ); document.write( "4*5R - 4*4S = 4*-17 \n" ); document.write( "5*4R + 5*5S = 5*52\r \n" ); document.write( "\n" ); document.write( "Simplifying these we have:\r \n" ); document.write( "\n" ); document.write( "3.) 20R - 16S = -68 \n" ); document.write( "4.) 20R + 25S = 260\r \n" ); document.write( "\n" ); document.write( "Subtracting equation 4.) from 3.) we then have:\r \n" ); document.write( "\n" ); document.write( "-41S = -328 \n" ); document.write( "S = 8\r \n" ); document.write( "\n" ); document.write( "Substitute 8 for S in either of the original two equations and calculate R.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |