document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263086>Question 263086</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Translate the problem into a pair of linear equations in two vaiables. Solve the equations using either elimination or substitution. State your answer for the specified variable.\r<BR>\n" );
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document.write( "Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 per pound. How many pounds of the cheaper kind should they use in the mix? \r<BR>\n" );
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document.write( "I just need to know what the two linear problems are, I can finish the problem from there. I just can't figure out how to get two problems from this. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193814 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tim and Judy mix two kinds of feed for pedigreed dogs. <BR>\n" );
document.write( "They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 per pound.<BR>\n" );
document.write( " How many pounds of the cheaper kind should they use in the mix?<BR>\n" );
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document.write( "Let x = amt of .24/lb required (the cheaper kind)<BR>\n" );
document.write( "Let y = amt of .42/lb required<BR>\n" );
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document.write( "The total pounds equation<BR>\n" );
document.write( "x + y = 54<BR>\n" );
document.write( "which is<BR>\n" );
document.write( "y = (54-x), use this for substitution<BR>\n" );
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document.write( "The total cost/lb equation<BR>\n" );
document.write( ".24x + .42y = .28(54)<BR>\n" );
document.write( ".24x + .42y = 15.12<BR>\n" );
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document.write( "You should be able solve this by substituting (54-x) for y in the above equation  </SPAN>\n" );
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