document.write( "Question 262931: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? \r
\n" ); document.write( "\n" ); document.write( "A. 2 hours
\n" ); document.write( "B. 4 ½ hours
\n" ); document.write( "C. 5 ¾ hours
\n" ); document.write( "D. 6 hours
\n" ); document.write( "E. 7 ½ hours \r
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Algebra.Com's Answer #193806 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I have a stopwatch and I'll start it when the 2nd
\n" ); document.write( "cyclist leaves. At that time the 1st cyclist has gone
\n" ); document.write( "\"r%5B1%5D%2A3\"
\n" ); document.write( "\"6%2A3+=+18\" mi
\n" ); document.write( "Now they will each go for the same time on my stopwatch, so
\n" ); document.write( "\"t%5B1%5D+=+t%5B2%5D\", which I'll just call \"t\"
\n" ); document.write( "\"d%5B1%5D+=+r%5B1%5D%2At\"
\n" ); document.write( "\"d%5B2%5D+=+r%5B2%5D%2At\"
\n" ); document.write( "From these,
\n" ); document.write( "\"d%5B1%5D%2Fr%5B1%5D+=+d%5B2%5D%2Fr%5B2%5D\"
\n" ); document.write( "\"d%5B1%5D%2Ar%5B2%5D+=+d%5B2%5D%2Ar%5B1%5D\"
\n" ); document.write( "\"10d%5B1%5D+=+6d%5B2%5D\"
\n" ); document.write( "\"d%5B1%5D+=+.6d%5B2%5D\"
\n" ); document.write( "I know 1 more thing about the distances:
\n" ); document.write( "\"d%5B2%5D+=+d%5B1%5D+%2B+18\", since the 2nd cyclist has to make up
\n" ); document.write( "the headstart the 1st one got
\n" ); document.write( "Substituting:
\n" ); document.write( "\"d%5B2%5D+=+.6d%5B2%5D+%2B+18\"
\n" ); document.write( "\".4d%5B2%5D+=+18\"
\n" ); document.write( "\"d%5B2%5D+=+45\" mi
\n" ); document.write( "and
\n" ); document.write( "\"d%5B1%5D+=+.6%2Ad%5B2%5D\"
\n" ); document.write( "\"d%5B1%5D+=+.6%2A45\"
\n" ); document.write( "\"d%5B1%5D+=+27\" mi
\n" ); document.write( "Now, I need to find \"t\"
\n" ); document.write( "(1) \"d%5B1%5D+=+r%5B1%5D%2At\"
\n" ); document.write( "(2) \"d%5B2%5D+=+r%5B2%5D%2At\"
\n" ); document.write( "-------------------
\n" ); document.write( "(1) \"27+=+6t\"
\n" ); document.write( "\"t+=+4.5\" hrs
\n" ); document.write( "and, also
\n" ); document.write( "(2) \"45+=+10t\"
\n" ); document.write( "\"t+=+4.5\" hrs
\n" ); document.write( "How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
\n" ); document.write( "This means that the 3 hr headstart is not to be included in answer
\n" ); document.write( "so, 4.5 hrs will pass
\n" ); document.write( "The answer is B\r
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