document.write( "Question 263044: Sorry I just wanted to make sure the problem I sumitted earlier was correct.\r
\n" ); document.write( "\n" ); document.write( "The correct problem is:2y^2+5y=3
\n" ); document.write( "read as follows:2y(squared)+5y=3 \r
\n" ); document.write( "\n" ); document.write( "did not understand where the x is coming from in the previous solution, there is no x in the problem.
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Algebra.Com's Answer #193794 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for y:
\n" ); document.write( "\"2y%5E2%2B5y+=+3\" Subtract 3 from both sides.
\n" ); document.write( "\"2y%5E2%2B5y-3+=+0\" Factor.
\n" ); document.write( "\"%282y-1%29%28y%2B3%29+=+0\" so...
\n" ); document.write( "\"2y+=+1\" or \"y+=+-3\"
\n" ); document.write( "\"highlight%28y+=+1%2F2%29\" or \"highlight%28y+=+-3%29\"
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