document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263029>Question 263029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are compementary.  The sum of the measure of the first angle and one-fourth the second angle is 66degrees.  Find the measures of the angles.  What is the measure of the smaller angle?  What is the measure of the other angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193785 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193785\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary.<BR>\n" );
document.write( "x and 90-x<BR>\n" );
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document.write( "The sum of the measure of the first angle and one-fourth the second angle is 66 degrees.<BR>\n" );
document.write( "90-x + (1/4)x = 66<BR>\n" );
document.write( "(-3/4)x = -24 <BR>\n" );
document.write( "x = 32 degrees<BR>\n" );
document.write( "90-x = 58 degrees<BR>\n" );
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document.write( "Find the measures of the angles. <BR>\n" );
document.write( "What is the measure of the smaller angle? <BR>\n" );
document.write( "What is the measure of the other angle?\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );