document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=263028>Question 263028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A can of vegetables has a diameter of 9.8 cm and is 13.2 cm tall. How much paper is required to make the label, assuming there is no overlap? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193780 by </B><A HREF=/tutors/aboutme.mpl?userid=georgiabh><B>georgiabh(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=georgiabh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to find the surface area of the sides of the can.  <BR>\n" );
document.write( "Imagine that this label, before being wrapped around the can would actually be a rectangle.  <BR>\n" );
document.write( "The area of a rectangle is its' height x  width.  <BR>\n" );
document.write( "The height is 13.2 cm. <BR>\n" );
document.write( "The width is the the length of the paper going around the can which is the circumference of the can.  <BR>\n" );
document.write( "The circumference of a circle is given by the equation pi x D where D is the diameter of the can which is pi x 9.8<BR>\n" );
document.write( "So the answer is pi x 9.8 x 13.2 <BR>\n" );
document.write( "So the area of the paper required is 406.4 cm sq. </SPAN>\n" );
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